@BeginModule
@NewPage
@Name      = Hourstat
@Title     = Hourly statistical values
@Section   = Statistical values
@Class     = Statistic
@Arguments = ifile ofile
@Operators = hourmin hourmax hoursum hourmean houravg hourstd

@BeginDescription
This module computes statistical values over time steps of the same hour.
Depending on the actual operator the minimum, maximum, sum, average 
or standard deviation of time steps of the same hour is written to @file{ofile}.
The date information for a time step in @file{ofile} is the date of the last 
contributing time step in @file{ifile}.
@EndDescription
@EndModule


@BeginOperator_hourmin
@Title     = Hourly minimum

@BeginDescription
@IfMan
For every adjacent sequence t_1, ...,t_n of time steps of the same hour, it is

o(t,x) = min{i(t',x), t_1<t'<=t_n}
@EndifMan
@IfDoc
For every adjacent sequence \begin{math}t_1, ...,t_n\end{math} of time steps of the same hour, it is: \\
@BeginMath
o(t,x) = \mbox{\bf min}\{i(t',x), t_1 < t' \leq t_n\}
@EndMath
@EndifDoc
@EndDescription
@EndOperator


@BeginOperator_hourmax
@Title     = Hourly maximum

@BeginDescription
@IfMan
For every adjacent sequence t_1, ...,t_n of time steps of the same hour, it is

o(t,x) = max{i(t',x), t_1<t'<=t_n}
@EndifMan
@IfDoc
For every adjacent sequence \begin{math}t_1, ...,t_n\end{math} of time steps of the same hour, it is: \\
@BeginMath
o(t,x) = \mbox{\bf max}\{i(t',x), t_1 < t' \leq t_n\}
@EndMath
@EndifDoc
@EndDescription
@EndOperator


@BeginOperator_hoursum
@Title     = Hourly sum

@BeginDescription
@IfMan
For every adjacent sequence t_1, ...,t_n of time steps of the same hour, it is

o(t,x) = sum{i(t',x), t_1<t'<=t_n}
@EndifMan
@IfDoc
For every adjacent sequence \begin{math}t_1, ...,t_n\end{math} of time steps of the same hour, it is: \\
@BeginMath
o(t,x) = \mbox{\bf sum}\{i(t',x), t_1 < t' \leq t_n\}
@EndMath
@EndifDoc
@EndDescription
@EndOperator


@BeginOperator_hourmean
@Title     = Hourly mean

@BeginDescription
@IfMan
For every adjacent sequence t_1, ...,t_n of time steps of the same hour, it is

o(t,x) = mean{i(t',x), t_1<t'<=t_n}
@EndifMan
@IfDoc
For every adjacent sequence \begin{math}t_1, ...,t_n\end{math} of time steps of the same hour, it is: \\
@BeginMath
o(t,x) = \mbox{\bf mean}\{i(t',x), t_1 < t' \leq t_n\}
@EndMath
@EndifDoc
@EndDescription
@EndOperator


@BeginOperator_houravg
@Title     = Hourly average

@BeginDescription
@IfMan
For every adjacent sequence t_1, ...,t_n of time steps of the same hour, it is

o(t,x) = avg{i(t',x), t_1<t'<=t_n}
@EndifMan
@IfDoc
For every adjacent sequence \begin{math}t_1, ...,t_n\end{math} of time steps of the same hour, it is: \\
@BeginMath
o(t,x) = \mbox{\bf avg}\{i(t',x), t_1 < t' \leq t_n\}
@EndMath
@EndifDoc
@EndDescription
@EndOperator


@BeginOperator_hourstd
@Title     = Hourly standard deviation

@BeginDescription
@IfMan
For every adjacent sequence t_1, ...,t_n of time steps of the same hour, it is

o(t,x) = std{i(t',x), t_1<t'<=t_n}
@EndifMan
@IfDoc
For every adjacent sequence \begin{math}t_1, ...,t_n\end{math} of time steps of the same hour, it is: \\
@BeginMath
o(t,x) = \mbox{\bf std}\{i(t',x), t_1 < t' \leq t_n\}
@EndMath
@EndifDoc
@EndDescription
@EndOperator


@BeginExample
To compute the hourly mean of a time series, use:
@BeginVerbatim
   cdo hourmean ifile ofile
@EndVerbatim
@EndExample
